NTA Abhyas JEE Main2020MathematicsComplex NumberPractice
Let α and β be the roots of x 2 + x + 1 = 0, then the equation whose roots are α 2020 and β 2020 is
Options
- Ax 2 + x + 1 = 0
- Bx 2 - x - 1 = 0
- Cx 2 + x - 1 = 0
- Dx 2 - x + 1 = 0
Correct answer
A. x 2 + x + 1 = 0
Step-by-step solution
x 2 + x + 1 = 0 ⇒ x = ω , ω 2 ⇒ α = ω and ⇒ β = ω 2 ⇒ α 2020 = ω 2020 = ω 3 673 . ω = ω ⇒ β 2020 = ω 2 2020 = ω 3 2 × 673 × ω 2 = ω 2 ⇒ The required equation is x 2 + x + 1 = 0