NTA Abhyas JEE Main2020MathematicsComplex NumberPractice
The real values of x and y for which the equation ( x 4 + 2 x i ) − ( 3 x 2 + y i ) = ( 3 − 5 i ) + ( 1 + 2 y i ) is satisfied, are
Options
- Ax = 2 , y = 3
- Bx = − 2 , y = 1 3
- Cx = ± 2 and y = 3 , 1 3
- DNone of these
Correct answer
C. x = ± 2 and y = 3 , 1 3
Step-by-step solution
Given equation ( x 4 + 2 x i ) − ( 3 x 2 + y i ) = ( 3 − 5 i ) + ( 1 + 2 y i ) ⇒ ( x 4 − 3 x 2 ) + i ( 2 x − 3 y ) = 4 − 5 i Equating real and imaginary parts, we get x 4 − 3 x 2 = 4 ......(i) and 2 x − 3 y = − 5 .....(ii) From (i) and (ii), we get x = ± 2 and y = 3 , 1 3