NTA Abhyas JEE Main2020MathematicsComplex NumberPractice
If α , β ∈ C are the distinct roots of the equation x 2 - x + 1 = 0 , then α 101 + β 107 is equal to
Options
- A2
- B- 1
- C0
- D1
Correct answer
D. 1
Step-by-step solution
x 2 - x + 1 = 0 Roots are - ω ,   - ω 2 α 101 + β 107 = - ω 101 + - ω 2 107 = - ω 2 - ω = 1