NTA Abhyas 2020
- Exam
- NTA Abhyas
- Year
- 2020
- Subject
- Mathematics
- Chapter
- Continuity and Differentiability
NTA Abhyas 2020 · Mathematics · Continuity and Differentiability
If f(x) = \ cases ( 2x)/(cx) + x 4( x + a ^ 2 - a) & ; x ≠ 0, (a...
If f\left(x\right) = \left\{\begin{cases}\dfrac{\sin 2x}{cx} + \dfrac{x}{4\left(\sqrt{x + {a}^{2}} - a\right)} & ; x \ne 0, \left(a < 0, c \ne 0\right) \\ b & ; x = 0, \left(b \ne 0\right)\end{cases}\right)</p> <p>andf\left(x\right)x = 0bc is equal to
Correct answer
2
Step-by-step solution
\left(x\right)x = 0∴ \lim_{x \to 0}f\left(x\right) = f\left(0\right)\lim_{x \to 0}\dfrac{\sin 2x}{cx} + \dfrac{x}{4\left(\sqrt{x + {a}^{2}} - a\right)}\left(\dfrac{\sqrt{x + {a}^{2}} + a}{\sqrt{x + {a}^{2}} + a}\right) = b\lim_{x \to 0}\dfrac{2}{c} + \dfrac{x\left(\sqrt{x + {a}^{2}} + a\right)}{4\left(\left(x + {a}^{2}\right) - {a}^{2}\right)} = b ⇒ \dfrac{2}{c} + 0 = b ( asa < 0 )⇒ bc = 2