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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Mathematics
Chapter
Continuity and Differentiability

NTA Abhyas 2020 · Mathematics · Continuity and Differentiability

If f(x) = \ cases ( 2x)/(cx) + x 4( x + a ^ 2 - a) & ; x ≠ 0, (a...

If f\left(x\right) = \left\{\begin{cases}\dfrac{\sin 2x}{cx} + \dfrac{x}{4\left(\sqrt{x + {a}^{2}} - a\right)} & ; x \ne 0, \left(a < 0, c \ne 0\right) \\ b & ; x = 0, \left(b \ne 0\right)\end{cases}\right)</p> <p>andf\left(x\right)iscontinuousatis continuous atx = 0,thenthevalueof, then the value ofbc is equal to

Correct answer

2

Step-by-step solution

∵f∵ f\left(x\right)iscontinuousatis continuous atx = 0<br/><br />∴ \lim_{x \to 0}f\left(x\right) = f\left(0\right)<br/><br />\lim_{x \to 0}\dfrac{\sin 2x}{cx} + \dfrac{x}{4\left(\sqrt{x + {a}^{2}} - a\right)}\left(\dfrac{\sqrt{x + {a}^{2}} + a}{\sqrt{x + {a}^{2}} + a}\right) = b<br/><br />\lim_{x \to 0}\dfrac{2}{c} + \dfrac{x\left(\sqrt{x + {a}^{2}} + a\right)}{4\left(\left(x + {a}^{2}\right) - {a}^{2}\right)} = b ⇒ \dfrac{2}{c} + 0 = b ( asa < 0 )<br/><br />⇒ bc = 2
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