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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Mathematics
Chapter
Continuity and Differentiability

NTA Abhyas 2020 · Mathematics · Continuity and Differentiability

If f(x) = \ array ll ( 2 ^ x - 1) ^ 2 3x xsi n ^ 2 x λ array array...

If f\left(x\right) = \left\{(2x−1)2tan⁡3xxsin2xλ\begin{array}{ll}\dfrac{{\left({2}^{x} - 1\right)}^{2}\tan 3x}{xsi{n}^{2}x} \\ \lambda\end{array}\right::\begin{array}{ll}: \\ :\end{array}$\begin{array}{ll}0 < x < \dfrac{\pi}{6} \\ x = 0\end{array} is continuous at x=0x = 0, then the value of $\dfrac{10\sqrt{3\lambda}}{\ln 2} is equal to

Correct answer

30

Step-by-step solution

∵f∵ f\left(x\right)iscontinuousatis continuous atx = 0<br/><br />∴ \lim_{x \to 0}f\left(x\right) = f\left(0\right)<br/><br />∵ \lim_{x \to {0}^{+}}\dfrac{{\left({2}^{x} - 1\right)}^{2}\tan 3x}{x . \sin^{2}x} = \lambda<br/><br />∵ \lim_{x \to {0}^{+}}{\left(\dfrac{{2}^{x} - 1}{x}\right)}^{2}\dfrac{\tan 3x}{\left(3x\right)} . \dfrac{\left(3x\right)}{x}\dfrac{{x}^{2}}{si{n}^{2}x} = \lambda<br/><br />{\left(\ln 2\right)}^{2} . 1.3 . 1 = \lambda<br/><br />\dfrac{10\sqrt{3\lambda}}{\ln 2} = 30
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