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If a , b and c are distinct positive real numbers such that Δ 1 = a b c b c a c a b and Δ 2 = b c - a 2 a c - b 2 a b - c 2 a c - b 2 a b - c 2 b c - a 2 a b - c 2 b c - a 2 a c - b 2 , then

Options

  1. AΔ 1 = Δ 2
  2. BΔ 1 2 + Δ 2 = 0
  3. CΔ 1 2 = Δ 2
  4. DΔ 1 2 = Δ 2 2

Correct answer

C. Δ 1 2 = Δ 2

Step-by-step solution

Elements of Δ 2 are co-factors of the elements of Δ 1 Hence Δ 1 2 = Δ 2

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