NTA Abhyas JEE Main2020MathematicsDeterminantsPractice
Let A = 1 3 cos ⁡ 2 θ 1 sin ⁡ 2 θ 1 3 cos ⁡ 2 θ 1 sin ⁡ 2 θ 1 . If the maximum value of A is equal to k , then k - 3 2 is equal to
Correct answer
49
Step-by-step solution
A = 1 1 - 3 sin 2 θ cos 2 θ - 3 cos 2 θ sin 2 θ - 3 cos 2 θ + 1 sin 2 2 θ - 1 = 1 - 3 sin 4 θ + 9 cos 2 2 θ + sin 2 2 θ - 1 = 1 - 3 sin 4 θ + 1 + 8 cos 2 2 θ - 1 = 1 - 3 sin 4 θ + 4 + 4 cos 4 θ A = 5 - 3 sin 4 θ + 4 cos 4 θ A m a x = 10