NTA Abhyas JEE Main2020MathematicsDeterminantsPractice
If f θ = cos 2 ⁡ θ cos ⁡ θ sin ⁡ θ - sin ⁡ θ cos ⁡ θ sin ⁡ θ sin 2 ⁡ θ cos ⁡ θ sin ⁡ θ - cos ⁡ θ 0 then, f π 6 + f π 3 + f π 2 + f 2 π 3 + f 5 π 6 + f π + . … … . + f 53 π 6 is equal to
Correct answer
53
Step-by-step solution
f θ = cos 2 θ cos 2 θ - cos θ sin θ - cos θ sin θ - sin θ - cos 2 θ sin θ - sin 3 θ = cos 4 θ + sin 4 θ + 2 cos 2 θ sin 2 θ = cos 2 θ + sin 2 θ 2 = 1 f π 6 = f 2 π 6 = f 3 π 6 = . … … . = f 53 π 6 = 1