NTA Abhyas JEE Main2020MathematicsDeterminantsPractice
If 2 + x x x 2 x 2 + x x 2 x 2 x 2 + x = 1 6 x - a x - b x - c x - d be an identity in x where a , b , c , d are independent of x , then the value of 13 25 a b c d is
Correct answer
24.96
Step-by-step solution
Since, the given equation is an identity in x , putting x = 0 , we get, 2 0 0 0 2 0 0 0 2 = 1 6 a b c d ⇒ a b c d = 48 ⇒ 13 25 a b c d = 13 × 48 25 = 24.96