If one of the roots of the equation 7 6 x 2 - 25 2 x 2 - 25 2 x 2 - 25 3 7 = 0 is x = 3, then the sum of all other five roots is

Step-by-step solution

Let the roots of expansion of the given determinant is a , b , c , d , e and 3 (given) ∵ the given determinant represents a 6 degree polynomial and contains even power of x ∴ coefficient of x 5 = 0 ⇒ 3 + the sum of other roots = 0 ⇒ the sum of other roots = - 3