NTA Abhyas JEE Main2020MathematicsDifferentiationPractice
If y = cos x cos 2 x cos 4 x cos 8 x , then d y d x at x = π 2 is
Options
- A1
- B0
- C4
- D16
Correct answer
A. 1
Step-by-step solution
y = sin ⁡ 16 x 16 sin ⁡ x   ∵   cos ⁡ A cos ⁡ 2 A . . . . . . . . . cos ⁡ 2 n - 1 A = sin 2 n A 2 n sin ⁡ A So, d y d x = 1 16 sin ⁡ x ⋅ 16 cos ⁡ 16 x - sin ⁡ 16 x cos ⁡ x sin ⁡ x 2 Putting x = π 2 , we get, d y d x = 1 16 ⋅ 1.16 1 - 0 1 2 = 1