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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Mathematics
Chapter
Hyperbola

NTA Abhyas 2020 · Mathematics · Hyperbola

The locus of the midpoint of the chords of the hyperbola (x2)/(25)...

The locus of the midpoint of the chords of the hyperbola x225−y236=1\dfrac{x2}{25} - \dfrac{y2}{36} = 1 which passes through the point (2,4)\left(2, 4\right) is a hyperbola, whose transverse axis length (in units) is equal to

Options

  1. A165\dfrac{16}{5}
  2. B43\dfrac{4}{3}
  3. C85\dfrac{8}{5}
  4. D6125\dfrac{61}{25}

Correct answer

A. 165\dfrac{16}{5}

Step-by-step solution

The equation of the chord whose mid-point is (h,k)( h, k ) is T=S1T = {S}_{1}
⇒xh25−yk36=h225−k236⇒ \dfrac{xh}{25} - \dfrac{yk}{36} = \dfrac{h2}{25} - \dfrac{k2}{36}
Since it passes through \left(2, 4\right)<br/><br />\dfrac{2h}{25} - \dfrac{4k}{36} = \dfrac{h2}{25} - \dfrac{k2}{36} ⇒ \dfrac{h^{2} - 2h + 1}{25} - \dfrac{k^{2} - 4k + 4}{36} = \dfrac{1}{25} - \dfrac{4}{36}<br/>Hence,thelocusof(h,k)<br />Hence, the locus of \left(h, k\right) is
(x−1)2169−(y−2)26425=−1\dfrac{\left(x - 1\right)2}{\dfrac{16}{9}} - \dfrac{\left(y - 2\right)2}{\dfrac{64}{25}} = - 1
This is the equation of a hyperbola whose transverse axis length is 165\dfrac{16}{5}& units
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