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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Mathematics
Chapter
Indefinite Integration

NTA Abhyas 2020 · Mathematics · Indefinite Integration

The value of ∫ ( 101x) . ^ 99 xdx is (100x) ^ 100 x k + 5 , then...

The value of ∫(sin⁡101x).sin⁡99xdx∫ \left(\sin 101x\right) . \sin^{99} xdx is sin⁡(100x)sin⁡100xk+5\dfrac{\sin \left(100x\right)\sin^{100} x}{k + 5}, then k19\dfrac{k}{19} is

Correct answer

5

Step-by-step solution

I=∫(sin⁡100x⋅cosx+cos⁡100x⋅sinx)sin⁡99x⋅dxI = ∫ \left(\sin 100x ⋅ cos x + \cos 100x ⋅ sin x\right)\sin^{99} x ⋅ dx
I=∫sin⁡100x⋅cosx.sin⁡99xdx+∫cos⁡100x⋅sin⁡100x⋅dxIIII = ∫ \sin 100x ⋅ cos x . \sin^{99} xdx + ∫ \cos 100x ⋅ \sin^{100} x ⋅ dxIII
I=sin⁡(100x)sin⁡100x100−100100∫cos⁡(100x)sin⁡100xdx+∫cos⁡(100x).sin⁡100x⋅dxI = \dfrac{\sin \left(100x\right)\sin^{100} x}{100} - \dfrac{100}{100}∫ \cos \left(100x\right)\sin^{100} xdx + ∫ \cos \left(100x\right) . \sin^{100} x ⋅ dx
I=sin⁡(100x)⋅sin⁡100x100+CI = \dfrac{\sin \left(100x\right) ⋅ \sin^{100} x}{100} + C
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