NTA Abhyas JEE Main2020MathematicsIndefinite IntegrationPractice
The value of the integral ∫ sin ⁡ x x 6 x c o s x - sin ⁡ x x 2 d x is (where, c is an arbitrary constant)
Options
- As i n x x + c
- Bs i n x x 2 + c
- Cs i n 7 x x 7 + c
- Ds i n 7 x 7 x 7 + c
Correct answer
D. s i n 7 x 7 x 7 + c
Step-by-step solution
Put s i n x x = t . Then, I = ∫ t 6 d t = t 7 7 + c