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The value of the integral ∫ x 2 - 4 x x + 6 x - 4 x + 1 x - 2 x + 1 d x is equal to

Options

  1. Ax 3 2 2 + x + c
  2. Bx 2 2 - 4 3 x 3 2 + x + c
  3. Cx 3 2 + x 2 + c
  4. D2 3 x 3 2 + c

Correct answer

B. x 2 2 - 4 3 x 3 2 + x + c

Step-by-step solution

Ι = ∫ x - 1 4 x - 1 2 d x = ∫ x - 1 2 d x = ∫ x - 2 x + 1 d x = x 2 2 - 4 3 x 3 2 + x + c

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