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NTA Abhyas JEE Main2020MathematicsIndefinite IntegrationPractice

The value of ∫ x - 4 x 2 x - 2 d x is equal to (where, C is the constant of integration)

Options

  1. A2 x x - 2 + C
  2. B- 2 x x - 2 + C
  3. Cx - 2 x + C
  4. Dx x - 2 + C

Correct answer

B. - 2 x x - 2 + C

Step-by-step solution

∫ x - 4 x 2 x - 2 d x ∫ 1 x 2 - 4 x 3 1 x - 2 x 2 d x Let 1 x - 2 x 2 = t - 1 x 2 + 4 x 3 d x = d t ∫ - d t t = - 2 t + C = - 2 1 x - 2 x 2 + C = - 2 x x - 2 + C

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