NTA Abhyas JEE Main2020MathematicsIndefinite IntegrationPractice
The value of ∫ 1 2 x - 1 x 2 - x d x is equal to (where c is the constant of integration)
Options
- As e c - 1 x - 1 + c
- Bs e c - 1 2 x - 1 + c
- Ct a n - 1 x + c
- Dt a n - 1 2 x - 1 + c
Correct answer
B. s e c - 1 2 x - 1 + c
Step-by-step solution
∫ 2 2 x - 1 4 x 2 - 4 x d x = 2 ∫ d x 2 x - 1 2 x - 1 2 - 1 = 2 × 1 2 s e c - 1 2 x - 1 + c