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NTA Abhyas JEE Main2020MathematicsIndefinite IntegrationPractice

The value of the ∫ s i n 8 x - c o s 8 x 1 - 2 s i n 2 x c o s 2 x d x is equal to (where, C is the constant of integration)

Options

  1. Asin ⁡ 2 x 2 + C
  2. B- sin ⁡ 2 x 2 + C
  3. Ccos ⁡ 2 x + C
  4. Dcos ⁡ x 2 + C

Correct answer

B. - sin ⁡ 2 x 2 + C

Step-by-step solution

Ι = ∫ s i n 4 x + c o s 4 x s i n 2 x + c o s 2 x s i n 2 x - c o s 2 x 1 - 2 s i n 2 x c o s 2 x d x Ι = ∫ - cos ⁡ 2 x d x = - 1 2 sin ⁡ 2 x + C

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