NTA Abhyas JEE Main2020MathematicsIndefinite IntegrationPractice
If the integral I = ∫ x x - 3 x + 3 x - 1 x - 2 x + 1 d x = f x + C (where, x > 0 and C is the constant of integration) and f 1 = - 1 3 , then the value of f 9 is equal to
Options
- A3
- B6
- C9
- D12
Correct answer
C. 9
Step-by-step solution
Given integral is I = ∫ x - 1 3 x - 1 2 d x = ∫ x - 1 d x = 2 3 x 3 2 - x + C ∴ f x = 2 3 x 3 2 - x ⇒ f 9 = 18 - 9 = 9