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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Mathematics
Chapter
Indefinite Integration

NTA Abhyas 2020 · Mathematics · Indefinite Integration

If the integral I = ∫ x x - 3x + 3 x - 1 x - 2 x + 1 dx= f(x) + C...

If the integral I=∫xx−3x+3x−1x−2x+1dx=f(x)+CI = ∫ \dfrac{x\sqrt{x} - 3x + 3\sqrt{x} - 1}{x - 2\sqrt{x} + 1}dx= f\left(x\right) + C (where, x>0x > 0 and& CC is the constant of integration)andf(1)=−13,and f \left(1\right) = \dfrac{- 1}{3}, then the value of& f(9)f\left(9\right)& is equal to

Options

  1. A33
  2. B66
  3. C99
  4. D1212

Correct answer

C. 99

Step-by-step solution

Given integral is I=∫(x−1)3(x−1)2dxI = ∫ \dfrac{{\left(\sqrt{x} - 1\right)}^{3}}{{\left(\sqrt{x} - 1\right)}^{2}}dx
=∫(x−1)dx= ∫ \left(\sqrt{x} - 1\right)dx
=23x32−x+C= \dfrac{2}{3}x^{\dfrac{3}{2}} - x + C
∴f(x)=23x32−x∴ f\left(x\right) = \dfrac{2}{3}x^{\dfrac{3}{2}} - x
⇒f(9)=18−9=9⇒ f\left(9\right) = 18 - 9 = 9
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