NTA Abhyas JEE Main2020MathematicsIndefinite IntegrationPractice
Let f x = 2 x + 1 and g x = ∫ f x x 2 x + 1 2 d x . If 6 g 2 + 1 = 0 , then g - 1 2 is equal to
Options
- A4
- B- 4
- C3
- D2
Correct answer
A. 4
Step-by-step solution
g x = ∫ x + 1 2 - x 2 x 2 x + 1 2 d x = ∫ 1 x 2 - 1 x + 1 2 d x = - 1 x + 1 x + 1 + c = - 1 x x + 1 + c g 2 = - 1 6 + c = - 1 6 ⇒ c = 0 Hence, g - 1 2 = 4