If _ x → 0 ( 2x - asin x)/(x3) exists finitely, then the value of a...

\lim_{x \to 0}\dfrac{sin x \left(2cos x - a\right)}{x ⋅ x^{2}} = \lim_{x \to 0} \left(\dfrac{sin x}{x}\right)\left(\dfrac{2cos x - a}{x2}\right)
For this limit$to$exists finitely,
\lim_{x \to 0}\dfrac{2cos x - a}{x^{2}} =$finite$
$∴$ It must be \dfrac{0}{0} form
$∴ 2\cos \left(0\right)$- a = 0 ⇒ a = 2