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NTA Abhyas JEE Main2020MathematicsLimitsPractice

The value of l i m x → ∞ e x + 1 l o g x 3 e - x + 1 s i n 3 2 x is equal to (Use e = 2.7 )

Correct answer

0.34

Step-by-step solution

Given, l i m x → ∞ e ⋅ e x l o g x 3 e x + 1 sin ⁡ 2 x 3 = l i m x → ∞ e     l o g x 3 e x + 1 x 3 e x × 2 x 3 sin ⁡ 2 x 3 × 1 8 = e × 1 × 1 × 1 8 = e 8 ∵ x 3 e x → 0   if   x → ∞

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