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The value of l i m x → π s i n 2 π c o s 2 x t a n π s e c 2 x is equal to

Options

  1. A1
  2. B2
  3. C- 2
  4. D0

Correct answer

C. - 2

Step-by-step solution

l i m x → π s i n 2 π 1 - s i n 2 x t a n π 1 + t a n 2 x = l i m x → π s i n 2 π - 2 π s i n 2 x t a n π + π t a n 2 x = l i m x → π - s i n 2 π s i n 2 x t a n π t a n 2 x = lim x → π - sin 2 π sin 2 x 2 π sin 2 x × 2 π sin 2 x π tan 2 x × π tan 2 x tan π tan 2 x = - 1 × 2 × 1 = - 2

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