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NTA Abhyas JEE Main2020MathematicsLimitsPractice

The value of l i m x → 1 x 2 5 - 2 x 5 + 1 x - 1 2 is equal to

Correct answer

0.04

Step-by-step solution

l i m x → 1 x 2 5 - 2 x 5 + 1 x - 1 2 = l i m x → 1 y 2 - 2 y + 1 y 5 - 1 2 P u t t i n g   x 5 = y ,   as   x → 1 ,   y → 1 l i m y → 1 y - 1 2 y - 1 2 y 4 + y 3 + y 2 + y + 1 2 = 1 25

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