NTA Abhyas JEE Main2020MathematicsLimitsPractice
The value of lim x → 1 ∑ r = 1 10 x r - 1 r 2 x - 1 is equal to
Correct answer
27.5
Step-by-step solution
We have, lim x → 1 ⁡ ∑ r = 1 10 x r - 1 r 2 x - 1 = 1 2 ∑ r = 1 10 r ⋅ 1 r - 1 = 1 + 2 + 3 + … + 10 2 = 10 10 + 1 4 = 55 2