NTA Abhyas JEE Main2020MathematicsLimitsPractice
The value of lim x → 0 1 - cos 3 x sin 2 x cos x is equal to
Correct answer
1.5
Step-by-step solution
lim x → 0 1 - cos 3 x sin 2 x cos x = lim x → 0 1 - cos x 1 + cos 2 x + cos x sin 2 x cos x = lim x → 0 2 sin 2 x 2 1 + cos 2 x + cos x 2 sin x 2 cos x 2 2 cos x = lim x → 0 1 2 ⋅ 1 + cos 2 x + cos x cos x 2 2 cos x = 1 2 3 1 = 3 2