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NTA Abhyas JEE Main2020MathematicsLimitsPractice

The value of lim x → 0 cos ⁡ x + sin ⁡ x 1 x is equal to (take e = 2 .71 )

Correct answer

2.71

Step-by-step solution

∵ lim x → a ⁡ f x ϕ x = e lim x → a ⁡ ϕ x f x - 1   as   f x → 1   &   ϕ x → ∞   as   x → a So, lim x → 0 cos ⁡ x + sin ⁡ x 1 x = e lim x → 0 ⁡ 1 x cos ⁡ x + sin ⁡ x - 1 = e lim x → 0 ⁡ - sin ⁡ x + cos ⁡ x 1 = e

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