NTA Abhyas JEE Main2020MathematicsLimitsPractice
The value of lim x → 2 ∑ r = 1 7 x r - 2 r 2 r x - 2 is equal to
Correct answer
63.5
Step-by-step solution
We have, ∑ r = 1 7 lim x → 2 ⁡ x r - 2 r 2 r x - 2 = ∑ r = 1 7 r ⋅ 2 r − 1 2 r = 1 + 2 1 + 2 2 + . … .. + 2 6 2 = 127 2