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NTA Abhyas JEE Main2020MathematicsLimitsPractice

The value of lim x → 0 ⁡ sin 2 ⁡ 3 x 3 + sec ⁡ x - 2 is equal to

Correct answer

72

Step-by-step solution

After rationalization, we get, lim x → 0 ⁡ sin 2 ⁡ 3 x 2 + 3 + sec ⁡ x 3 + sec ⁡ x - 4 = lim x → 0 sin 2 3 x 9 x 2 ⋅ 9 x 2 1 − cos x 2 + 3 + 1 = 9 2 4 = 72

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