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NTA Abhyas JEE Main2020MathematicsLimitsPractice

The value of lim x → 0 - ⁡ 4 3 x + 15 2 1 x 2 1 + 6 x + 6 2 1 x is equal to

Correct answer

2.5

Step-by-step solution

l i m x → 0 - 2 6 x + 15 ⋅ 2 1 x 2 1 + 6 x + 6 ⋅ 2 1 x = l i m x → 0 - 2 1 x 2 5 x + 15 2 1 x 2 2 5 x + 6 = lim x → 0 - ⁡ 2 5 x + 15 2 2 5 x + 6 = 0 + 15 2 0 + 6 = 15 6 = 5 2

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