NTA Abhyas JEE Main2020MathematicsLimitsPractice
The value of lim x → 0 + x cot x + x ln x is equal to
Options
- A1
- B2
- C3
- D0
Correct answer
A. 1
Step-by-step solution
lim x → 0 + ⁡ x cot ⁡ x + lim x → 0 + ⁡ x ln ⁡ x = lim x → 0 + ⁡ x tan ⁡ x + lim x → 0 + ⁡ ln ⁡ x 1 x = lim x → 0 + ⁡ x tan ⁡ x + lim x → 0 + ⁡ 1 x - 1 x 2 = 1 + lim x → 0 + ⁡ - x = 1 + 0 = 1