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NTA Abhyas JEE Main2020MathematicsLimitsPractice

The value of lim x → 0 ⁡ 1 + 6 x 1 3 - 1 + 4 x 1 2 x 2 is equal to

Options

  1. A1
  2. B2
  3. C- 1
  4. D- 2

Correct answer

D. - 2

Step-by-step solution

Using binomial expansion, the given limit becomes lim x → 0 1 + 2 x + 1 3 1 3 − 1 2 ! ⋅ 36 x 2 + … − 1 + 2 x + 1 2 1 2 − 1 2 ! ⋅ 16 x 2 + … x 2 = lim x → 0 ⁡ 2 - 4 x 2 + … x 2 = - 2

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