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NTA Abhyas JEE Main2020MathematicsParabolaPractice

If the normal at P 18,12 to the parabola y 2 = 8 x cuts it again at Q , then the equation of the normal at point Q on the parabola y 2 = 8 x is

Options

  1. A27 y = 99 x - 3058
  2. B27 y = 99 x + 3058
  3. C27 y = - 99 x - 3058
  4. DNone of these

Correct answer

A. 27 y = 99 x - 3058

Step-by-step solution

Let, 2 t 2 , 4 t = 18,12 & Q = 2 t 1 2 , 4 t 1 then t = 3   &   t 1 = - t - 2 t ⇒ t 1 = - 3 - 2 3 = - 11 3 Equation of the normal at Q is y = - t 1 x + 4 t 1 + 2 t 1 3 ⇒ y = 11 3 x - 44 3 - 2662 27 ⇒ 27 y = 99 x - 305 8

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