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The area of the quadrilateral formed by the tangents and normals at the extremities of the latus rectum of the parabola y 2 - 4 y + 4 + 12 x = 0 is

Options

  1. A36 s q . u n i t s
  2. B72 s q . u n i t s
  3. C144 s q . u n i t s
  4. D96 s q . u n i t s

Correct answer

B. 72 s q . u n i t s

Step-by-step solution

y - 2 2 = - 12 x The quadrilateral is a square with diagonal length = 12 ∴ Area = 1 2 × 12 × 12 = 72 sq. units

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