NTA Abhyas JEE Main2020MathematicsParabolaPractice
The equation of a straight line passing through the point 3 , 6 and normal to the curve y = x is
Options
- A4 x + y - 18 = 0
- Bx + y - 9 = 0
- C4 x - y - 6 = 0
- Dx - y + 3 = 0
Correct answer
A. 4 x + y - 18 = 0
Step-by-step solution
Normal to the parabola y 2 = x is y = m x - m 2 - m 3 4 Since, it passes through the point 3 , 6 ⇒ m 3 - 10 m + 24 = 0 ; m = - 4 is a root Hence, the required equation is 4 x + y - 18 = 0