NTA Abhyas 2020
- Exam
- NTA Abhyas
- Year
- 2020
- Subject
- Mathematics
- Chapter
- Sets and Relations
NTA Abhyas 2020 · Mathematics · Sets and Relations
Let P be the relation defined on the set of all real numbers such...
Let be the relation defined on the set of all real numbers such that . Then is&
Options
- Areflexive and symmetric but not transitive
- Bsymmetric and transitive but not reflexive
- Creflexive and transitive but not symmetric
- Dan equivalence relation
Correct answer
D. an equivalence relation
Step-by-step solution
\text{P} = \left\{\left(\text{a, b}\right) \text{:} \sec^{2} \text{a} - \tan^{2} \text{b} = 1\right\}\sec^{2} \text{a} - \tan^{2} \text{b} = 1⇒ \sec^{2} \text{a} = 1 + \tan^{2} \text{b}⇒ \sec^{2} \text{a} = \sec^{2} \text{b}⇒ \left|\text{sec a}\right| = \left|\text{sec b}\right|\sec^{2} \text{a} - \tan^{2} \text{b} = 11 + \tan^{2} \text{a} - \sec^{2} \text{b} + 1 = 1\sec^{2} \text{b} - \tan^{2} \text{a} = 1 and \left|\text{sec b}\right| = \left|\text{sec c}\right| transitive&
So it is an equivalence relation.
&
So it is an equivalence relation.
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