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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Mathematics
Chapter
Sets and Relations

NTA Abhyas 2020 · Mathematics · Sets and Relations

If A = \ x ∈ ℝ: |x| < 2\ and B = \ x ∈ ℝ: |x - 2| ≥ 3\ ; then

If A={x∈R:∣x∣<2}A = \left\{x \in \mathbb{R}: \left|x\right| < 2\right\} and B={x∈R:∣x−2∣≥3};B = \left\{x \in \mathbb{R}: \left|x - 2\right| \ge 3\right\}; then

Options

  1. AA∩B=(−2,−1)A \cap B = \left(-2, - 1\right)
  2. BB−A=R−(−2,5)B - A = \mathbb{R} - \left(-2, 5\right)
  3. CA∪B=R−(2,5)A \cup B = \mathbb{R} - \left(2, 5\right)
  4. DA−B=[−1,2)A - B = \left[-1, 2\right)

Correct answer

B. B−A=R−(−2,5)B - A = \mathbb{R} - \left(-2, 5\right)

Step-by-step solution

A={x:x∈(−2,2)}A = \left\{x: x \in \left(- 2,2\right)\right\}
B = \left\{x: x \in ( - \infty, - 1 ] \cup [ 5, \left\infty\right)\right\}
A∩B={x:x∈(−2,−1]}A \cap B = \left\{x: x \in ( - 2, - 1 ]\right\}
A \cup B = \left\{x: x \in \left(- \infty, 2\right) \cup \left[5, \infty )\right\right\}
A−B={x:x∈(−1,2)}A - B = \left\{x: x \in \left(- 1,2\right)\right\}
B - A = \left\{x: x \in \left(- \infty, \left- 2\right] \cup \left[5, \left\infty\right)\right\right\right\}
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