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NTA Abhyas JEE Main2020MathematicsStraight LinesPractice

The equation of the bisectors of the angles between the lines represented by the equation 2 x + 2 2 + 3 x + 2 y - 2 - 2 y - 2 2 = 0 is

Options

  1. A3 x 2 - 8 x y - 3 y 2 - 28 x + 4 y + 32 = 0
  2. B3 x 2 + 8 x y - 3 y 2 + 28 x - 4 y + 32 = 0
  3. C3 x 2 - 8 x y - 3 y 2 + 28 x - 4 y + 32 = 0
  4. D3 x 2 - 8 x y - 3 y 2 + 28 x - 4 y - 32 = 0

Correct answer

C. 3 x 2 - 8 x y - 3 y 2 + 28 x - 4 y + 32 = 0

Step-by-step solution

Equation of the bisectors would be x + 2 2 - y - 2 2 2 - - 2 = x + 2 ( y - 2 ) 3 2 3 x 2 + 4 x + 4 - y 2 + 4 y - 4 = 8 x y - 2 x + 2 y - 4 3 x 2 + 12 x - 3 y 2 + 12 y = 8 x y - 16 x + 16 y - 32 3 x 2 - 8 x y - 3 y 2 + 28 x - 4 y + 32 = 0

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