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NTA Abhyas JEE Main2020MathematicsStraight LinesPractice

The number of values of p for which the lines x + y - 1 = 0 ,   p x + 2 y + 1 = 0 and 4 x + 2 p y + 7 = 0 are concurrent is equal to

Options

  1. A0
  2. B2
  3. C1
  4. DInfinite

Correct answer

C. 1

Step-by-step solution

1 1 - 1 p 2 1 4 2 p 7 = 0 ⇒ 2 p 2 + 9 p - 26 = 0 ⇒ p = - 13 2 , 2 p = 2 is rejected because at p = 2 all 3 lines becomes parallel ⇒ Hence, p = - 13 2

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