NTA Abhyas JEE Main2020MathematicsStraight LinesPractice
Let ∆ A B C is an isosceles triangle with A B = A C . If B = 0 , a ,   C = 2 a , 0 and the equation of A B is 3 x - 4 y + 4 a = 0 , then the equation of side A C is
Options
- Ay = 8 x - 16 a
- B3 y = 4 x - 8 a
- Cx = 2 a
- Dy + 8 x = 16 a
Correct answer
C. x = 2 a
Step-by-step solution
Let, ∠ A B C = ∠ A C B = θ and slope of A C = m Slope of B C = - 1 2 Slope of A B = 3 4 Now, tan ∠ A B C = tan ∠ A C B ⇒ 3 4 - - 1 2 1 + 3 4 - 1 2 = - 1 2 - m 1 + - 1 2 m ⇒ 2 = - 1 2 - m 1 - m 2 ⇒ 2 - m = - 1 2 - m ⇒ m = not defined ⇒ equation of A C is x = 2 a