NTA Abhyas JEE Main2020MathematicsStraight LinesPractice
If 5 a + 4 b + 20 c = t , then the value of t for which the line a x + b y + c - 1 = 0 always passes through a fixed point is
Options
- A0
- B20
- C30
- DNone of these
Correct answer
B. 20
Step-by-step solution
Equation of the given line is a x + b y + c − 1 = 0 ⇒ 20 a x + 20 b y + 20 c − 20 = 0 .....(i) From the given relation, substituting value of c , we get, 20 a x + 20 b y + t − 5 a − 4 b − 20 = 0 ⇒ 20 a ( x − 1 4 ) + 20 b ( y − 1 5 ) + ( t − 20 ) = 0 Clearly for t = 20 , the given line will pass through the point ( 1 4 , 1 5 ) for all the values of a & b