NTA Abhyas JEE Main2020MathematicsStraight LinesPractice
The line 2 x + 3 y = 12 meets the coordinates axes at A and B respectively. The line through 5,5 perpendicular to A B meets the coordinate axes and the line A B at C , D and E respectively. If O is the origin, then the area (in sq. units) of the figure O C E B is equal to
Options
- A13 3
- B23 3
- C11
- D7
Correct answer
B. 23 3
Step-by-step solution
The equation of a line passing through P 5,5 and perpendicular to 2 x + 3 y = 12 is y - 5 = 3 2 x - 5 or, 3 x - 2 y - 5 = 0 The coordinates of the point of intersection of 2 x + 3 y - 12 = 0 and 3 x - 2 y - 5 = 0 are E 3,2 . The line 3 x - 2 y - 5 = 0 meets x -axis at C 5 3 , 0 . Now, A r e a  o f  f i g u r e  O C E B = A r e a  o f  Δ A O B - A r e a  o f  Δ A C E = 1 2 O A × O B - 1 2 A C × E L = 1 2 × 6 × 4 - 1 2 × 13 3 × 2 = 23 3