NTA Abhyas JEE Main2020MathematicsStraight LinesPractice
Let the circumcentre of ∆ A B C is S - 1 , 0 and the midpoints of the sides A B and A C are E 1 , - 2 and F - 2 , - 1 respectively, then the coordinates of A are
Options
- A0 , - 3
- B0 , 3
- C- 3 , 0
- D3 , 0
Correct answer
B. 0 , 3
Step-by-step solution
Slope of S F is 1 ⇒ Slope of A B is 1 Now, the slope of E S is - 1 ⇒ Slope of A C is - 1 Equation of A B is x + y + 3 = 0 Equation of A C is x - y - 3 = 0 Hence, point A is 0 , 3