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The maximum value of p for which the lines 3 x - 4 y = 2 ,   3 x - 4 y = 12 ,   12 x + 5 y = 7 and 12 x + 5 y = p constitute the sides of a rhombus is

Options

  1. A33
  2. B19
  3. C- 19
  4. D9

Correct answer

A. 33

Step-by-step solution

If the parallelogram is a rhombus, the distance between the pair of parallel sides are equal Hence, 12 - 2 3 2 + 4 2 = ± p - 7 12 2 + 5 2 ⇒ p - 7 = ± 26 ⇒ p = 33 or - 19 So the maximum value of p is 33

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