NTA Abhyas JEE Main2020MathematicsStraight LinesPractice
In the triangle A B C , vertices A , B , C are 1 , 2 , 3,1 , - 1,6 respectively. If the internal angle bisector of ∠ B A C meets B C at D , then the coordinates of D are
Options
- A5 3 , 8 3
- B1 , 7 2
- C1 3 , 13 3
- D2 , 3 4
Correct answer
A. 5 3 , 8 3
Step-by-step solution
A B = 5 , A C = 20 = 2 5 Since A D is the internal angle bisector, so D divides B C in the ratio of A B : A C ≡ 1 : 2 Now, applying section formula, we get, The coordinates of D as 6 - 1 2 + 1 , 2 + 6 2 + 1 ≡ 5 3 , 8 3