NTA Abhyas JEE Main2020MathematicsThree Dimensional GeometryPractice
If the lines L 1 : x - 1 3 = y - λ 1 = z - 3 2 and L 2 : x - 3 1 = y - 1 2 = z - 2 3 are coplanar, then the equation of the plane passing through the point of intersection of L 1 and L 2 which is at a maximum distance from the origin is
Options
- A3 x + 2 y + z = 5
- B2 x + 3 y + z = 6
- C4 x + 3 y + 5 z = 0
- D4 x + 3 y + 5 z = 50
Correct answer
D. 4 x + 3 y + 5 z = 50
Step-by-step solution
∵ L 1 and L 2 are coplanar, hence, - 2 λ - 1 1 3 1 2 1 2 3 = 0 ⇒ λ = 2 Now point of intersection will be P 4 , 3 , 5 ∴ Equation of required plane is 4 x + 3 y + 5 z = 50