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NTA Abhyas JEE Main2020MathematicsThree Dimensional GeometryPractice

If m 1 and m 2 are the roots of the equation x 2 + 3 + 2 x + 3 - 1 = 0 , then the area (in sq. units) of the triangle bounded by the lines y = m 1 x , y = m 2 x and y = 2 is

Options

  1. A33 + 11
  2. B33 - 11
  3. C2 33
  4. D2 11

Correct answer

A. 33 + 11

Step-by-step solution

Vertices of the triangle formed by the lines y = m 1 x , y = m 2 x & y = 2 are 0,0 , 2 m 1 , 2 & 2 m 2 , 2 Area of the triangle = 1 2 0 0 1 2 m 1 2 1 2 m 2 2 1 = 2 m 2 - m 1 m 1 m 2 = 2 D a c a = 2 D c = 2 b 2 - 4 a c c = 2 7 + 4 3 - 4 3 - 1 3 - 1 = 2 11 3 - 1 = 33 + 11 sq. units

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