NTA Abhyas JEE Main2020MathematicsThree Dimensional GeometryPractice
Direction cosines of the normal to the plane containing the lines x 2 = y 3 = z 5 and x - 1 2 = y - 1 3 = z - 1 5 are
Options
- A2 14 , - 3 14 , 5 14
- B2 14 , - 3 14 , 1 14
- C2 14 , - 1 14 , 1 14
- D3 13 , - 2 13 , 1
Correct answer
B. 2 14 , - 3 14 , 1 14
Step-by-step solution
The normal vector to the plane = i ^ j ^ k ^ 1 1 1 2 3 5 = 2 i ^ - 3 j ^ + k ^ Hence, direction cosines are 2 14 , - 3 14 , 1 14