NTA Abhyas JEE Main2020MathematicsThree Dimensional GeometryPractice
A plane P = 0 is the perpendicular bisector of the line joining the points 2,3 , 4 and 6,7 , 8 . The perpendicular distance of P = 0 from the origin is
Options
- A4 3 units
- B5 3 units
- C6 3 units
- D8 3 units
Correct answer
B. 5 3 units
Step-by-step solution
From diagram mid-point of A B must lie on the plane M 2 + 6 2 , 3 + 7 2 , 4 + 8 2 ≡ 4,5 , 6 A B is perpendicular to the required plane Direction ratios of A B → = < 4,4 , 4 > = < 1 , 1 , 1 > Equation of the required plane is 1 x - 4 + 1 y - 5 + 1 z - 6 = 0 ⇒ x + y + z = 15 The perpendicular distance from the origin to the plane = 0 + 0 + 0 - 15 3 = 5 3 units