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If x and y are the solutions of the equation 5 + 8 s i n 2 x = 2 y 2 - 8 y + 21 , then the least possible value of x 2 y 3 is

Options

  1. A2 π 2
  2. B4 π 2
  3. C9 π 2
  4. Dπ 2

Correct answer

A. 2 π 2

Step-by-step solution

∵ 5 + 8 s i n 2 x ∈ 5 , 13 Also, 2 y 2 - 8 y + 21 = 2 y - 2 2 + 13 ≥ 13 So, equality should hold true if, 5 + 8 s i n 2 x = 13 and 2 y 2 - 8 y + 21 = 13 ⇒ s i n x = ± 1 ,   y = 2 ⇒ s i n x = 2 n + 1 π 2 ,   y = 2 For least value, x = ± π 2 Hence, x 2 y 3 = π 2 4 · 8 = 2 π 2

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